United States → Ecuador
How long is the flight from New York to Galápagos?
3,026 miles
- From
JFKNew York
John F Kennedy International Airport
Departure 09:05 · America/New_York
- To
GPSGalápagos
Seymour Airport
Arrival 13:00 · Pacific/Galapagos
Route Details
The flight from John F Kennedy International Airport (JFK) in New York to Seymour Airport (GPS) in Galápagos covers a distance of approximately 4,870 kilometers (3,026 miles).
Direct flights typically take around 5 h 55 min, though actual flight times may vary depending on aircraft type, weather conditions, and air traffic.
Time Zone Information
- Departure Time Zone
- America/New_York
- Arrival Time Zone
- Pacific/Galapagos
Flight times shown account for local time zones at departure and arrival airports.
Frequently Asked Questions
How long is the flight from New York to Galápagos?
A direct flight from New York to Galápagos takes around 5 h 55 min. Actual flight times vary with the aircraft type, the weather conditions and air traffic.
What is the distance from New York to Galápagos?
The distance from New York to Galápagos is about 4,870 kilometers (3,026 miles) as the crow flies.
Is there a direct flight from New York to Galápagos?
Where the route is served nonstop, the flight takes around 5 h 55 min. On an itinerary with a connection, add the time spent on the ground at the layover airport.